Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trialAnkur Abichandani
182 Pointscall the printf method to print "<your name> can code in Java!"
i am not able to execute this. below is what i am typing and below that is the error i receive.
String firstName = "Ankur"; console.printf= ("%s can code in Java!", firstName );
Error- JavaTester.java:74: error: cannot find symbol printf= ("%s can code in Java!"); ^ symbol: variable printf location: class JavaTester Note: JavaTester.java uses or overrides a deprecated API. Note: Recompile with -Xlint:deprecation for details. 1 error
// I have setup a java.io.Console object for you named console
String firstName = "Ankur";
printf= ("%s can code in Java!");
JavaTester.java:74: error: cannot find symbol
printf= ("%s can code in Java!");
^
symbol: variable printf
location: class JavaTester
Note: JavaTester.java uses or overrides a deprecated API.
Note: Recompile with -Xlint:deprecation for details.
1 error
1 Answer
Alexis Beliveau
8,029 PointsSystem.out.printf ("%s can code in Java!" , firstName);
Seems you are missing System.out. Also, you have to list what the String in %s actually is.
This may help a little! (:
Ankur Abichandani
182 PointsAnkur Abichandani
182 PointsThanks alexis. i found that i putting an "=" symbol after printf, rather than just printf ("%s can code in java!", fistname);