Call the printf method on the console object and make it write out "<YOUR NAME> can code in Java!"

Hi Chris,

You have a couple of points in your code that aren't quite right. First; the output string is terminated too early. By this, I mean that you closed the string, like this "%s". But the rest of the words should be included in it; like this: "%s can code in Java!". Note where the closing inverted commas are placed.

Secondly, the %s placeholder marks a point within that string where the value of a variable will be inserted. In order to identify which variable, the name of the variable is placed within the parentheses of the printf method, separated from the string by a comma.

So, something like this:

String firstName = "Chris";
console.printf("%s can code in Java!", firstName);

This inserts the contents of firstName at the point where the %s is placed inside the output string.

I hope that helps. If not, please ask and I'll do a better job!

Steve.

You're very close! When the code runs Java will insert whatever value has been assigned to firstName in place of the string formatter (%s) You failed to define the (%s) so Java doesnt know what value to use, in this case it should be "firstName" so you can print your message you want in quotes, followed by a comma and then the value. Example: console.printf("%s can code in Java!", firstName)

System.out.prinf method requires a String, and the variable name that will hold the placeholder in the string.

String name = "YOUR_NAME"; System.out.printf("hello %s, name);