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1,820 PointsCall the function and pass in a value of 10 for the first parameter and 3 for the second. Assign the result of
I have assigned the result a constant named result. What am I doing wrong here?
// Enter your code below
func getRemainder(value a: Int, divisor b: Int) -> Int {
let operation = a % b
return operation
}
let result = getRemainder(value a: 10, divisor b: 3)
2 Answers
andren
28,558 PointsWhen you call the function you should't specify both value
and a
as parameter names. value
is the external label, meaning that is the label you use when you call the function. a
is the internal label, meaning that is the one you use within the function. The same is true of divisor
and b
.
So if you simply remove a
and b
from the call to the function like this:
func getRemainder(value a: Int, divisor b: Int) -> Int {
let operation = a % b
return operation
}
let result = getRemainder(value: 10, divisor: 3)
Then your code will work.
Tanner Hildebrandt
1,820 Pointsgreat! thank you andren!