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Python Python Basics (2015) Shopping List App Break

Daniel Sayre
Daniel Sayre
884 Points
Posted by Daniel Sayre
Daniel Sayre
884 Points

breaks.py. The break is throwing me for a loop

I have tried quite a few variations on this code but I just don't seem to be getting anything but errors.

breaks.py 
def loopy(items):
    # Code goes here
    for item in items:
        if items() !='DONE'
            print(items)
        else:
            break
Daniel Sayre
Daniel Sayre
884 Points
Daniel Sayre
Daniel Sayre
884 Points

I have also tried: def loopy(items): # Code goes here for item in items: if items() =='DONE': break else: print(items)

def loopy(items): # Code goes here for item in items: if items =='DONE': break else: print(items)

1 Answer

lemelleio
lemelleio
10,874 Points
lemelleio
lemelleio
10,874 Points

Hey Daniel,

Your code is almost right, you're just missing a few things.

For one, your if statement is missing a ':'

and remember you're iterating over a list called 'items' by 'item'

When you wrote your if statement you're trying to call 'items' like a function.

It should be 'item' since that's what you're iterating by.

lastly you should be printing the individual 'item' not 'items', which is the entire list that was passed into the loopy function.

def loopy(items):
    # Code goes here
    for item in items:
        if item !='DONE':
            print(item)
        else:
            break