breaks.py Exercise:
Skipping the List item in for loop

Question

I am trying to put below code for breaks.py exercise and in console it's working fine but the exercise is not accepting the answer.
def loopy(items):
    # Code goes here
    for no in items:
      if no == 'a':
        continue
      else:
        print(no)
loopy(items)
```breaks.py
def loopy(items):
    # Code goes here
    for no in items:
      if no == 'a':
        continue
      else:
        print(no)
loopy(items)
```

vipin kala · Answer

Hi Andreas, Thanks for the response. As you said I interpreted this question the same way first time and wrote the code as below. But even this won't work.
'''def loopy(items):
    # Code goes here
  if items[0] == 'a':
    items.remove('a')
  for no in items:
    print(no)'''

vipin kala · Answer

Hi Andreas,
   Thanks for the response.
As you said I interpreted this question the same way first time and wrote the code as below. But even this won't work.
def loopy(items):
    # Code goes here
  if items[0] == 'a':
    items.remove('a')
  for no in items:
    print(no)

Andreas cormack · Answer

Hi Vipin
there is a error in your code at line 4. You need to check if the items index 0 is 'a', you were checking against every item rather than the index 0 of each item.
so if you had a list like so ['a','n','d','r','e','w'], the code would print everything apart from index 0 which is the letter 'a'.
see below
```python
def loopy(items):
    # Code goes here
    for no in items:
      if no[0] == 'a':  # This is the line that caused the error. Your code was checking against every value rather than index 0
        continue
      else:
        print(no)
```
hope this helps

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vipin kala

vipin kala

breaks.py Exercise: Skipping the List item in for loop

3 Answers

Andreas cormack

Andreas cormack

vipin kala

vipin kala

vipin kala

vipin kala