Basic Exception Handling

Question

I do not know what this compiler error means; it would seem to imply that I don't have a try or catch, but I do.

I asked my friend about this and he said that I put the catch in the try block, but that doesn't mean much when I don't understand the exact function of both blocks. Based on that, I would remove the println from the try block, but then what? Do you necessarily have to have much of anything in the try block?

Example.java

class Example {

  public static void main(String[] args) {
    GoKart kart = new GoKart("purple");
    try {
      if (kart.isBatteryEmpty()) {
      System.out.println("The battery is empty");
      }
    }

    catch (IllegalArgumentException iae) {
      System.out.println("Not enough battery remains!);}

    kart.drive(42);
  }

}

GoKart.java

class GoKart {
  public static final int MAX_BARS = 8;
  private int barCount;
  private String color;
  private int lapsDriven;

  public GoKart(String color) {
    this.color = color;
  }

  public String getColor() {
    return color;
  }

  public void charge() {
    barCount = MAX_BARS;
  }

  public boolean isBatteryEmpty() {
    return barCount == 0;
  }

  public boolean isFullyCharged() {
    return MAX_BARS == barCount;
  }

  public void drive() {
    drive(1);
  }

  public void drive(int laps) {
    if (laps > barCount) {
      throw new IllegalArgumentException("Not enough battery remains");
    }
    lapsDriven += laps;
    barCount -= laps;
  }

}

Answer 1 · 2018-08-22T08:10:00Z

August 22, 2018 8:10am

first, you are missing a double-quote on the system.out.println() text on line 12 and the catch is supposed to directly in front of the try code block

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shiny peanut

shiny peanut

Basic Exception Handling

1 Answer

Ifueko agbontaen

Ifueko agbontaen