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Start your free trialTakyi Akwah
Courses Plus Student 1,049 PointsAVG Help
Can somebody please show me where I am getting the code wrong?
1 Answer
Alexander Davison
65,469 PointsThere's an extra comma after average_rating
.
Takyi Akwah
Courses Plus Student 1,049 PointsThank you. Shows why you must proof read.
Takyi Akwah
Courses Plus Student 1,049 PointsTakyi Akwah
Courses Plus Student 1,049 PointsWe're in a movie database. There's a reviews table with the columns of id, movie_id, username, review and rating.
The movie "Starman" has an id of 6. Movie ids are stored in the movie_id column. Calculate the average rating for "Starman". Alias the average as average_rating.
SELECT AVG(rating) AS average_rating, FROM reviews WHERE movie_id = 6;