Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Python Python Basics (2015) Letter Game App Even or Odd Loop

narapady chhuoy
narapady chhuoy
1,775 Points
Posted by narapady chhuoy
narapady chhuoy
1,775 Points

Anyone help me please

Alright, last step but it's a big one. Make a while loop that runs until start is falsey. Inside the loop, use random.randint(1, 99) to get a random number between 1 and 99. If that random number is even (use even_odd to find out), print "{} is even", putting the random number in the hole. Otherwise, print "{} is odd", again using the random number. Finally, decrement start by 1. I know it's a lot, but I know you can do it!

I am stuck with this code challenge. Anyone please help me! thank

even.py 
import random
def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2
start = 5
while start < 1:
    number = even_odd(random.randint(1, 99))
    if number = True:
        print("{} is even".format(number))
    else:
        print("{} is odd".format(number))
    start = start - 1

2 Answers

Jennifer Nordell
seal-mask
STAFF
.a{fill-rule:evenodd;}techdegree
Jennifer Nordell
Treehouse Teacher
Jennifer Nordell
.a{fill-rule:evenodd;}techdegree
Jennifer Nordell
Treehouse Teacher

Hi there! In addition to the answer left above, you have some other things going on. Your number variable is set to be equal to the result of running even_odd on the random number generated. Because of this number will only ever be equal to True or False and not a number. I would suggest using just the code to generate a random number and assign that random number to the variable number.

Furthermore, your else will never trigger. In your if statement, you a are not doing a comparison to True but rather an assignment to True. This will always succeed.

Instead, once you fix your while loop so that it begins as stated by Henrik Christensen, you should be doing a comparison on the evaluation of your random number passed into the even_odd function there. I would suggest:

if even_odd(number):

Hope this helps! :sparkles:

Henrik Christensen
seal-mask
.a{fill-rule:evenodd;}techdegree
Henrik Christensen
Python Web Development Techdegree Student 38,322 Points
Henrik Christensen
.a{fill-rule:evenodd;}techdegree
Henrik Christensen
Python Web Development Techdegree Student 38,322 Points

Have a look at this part while start < 1 it says "WHILE start IS LESS than 1" and since start = 5 IS GREATER than 1 the while-loop will never run.

I hope this helps :-)

narapady chhuoy
narapady chhuoy
1,775 Points
narapady chhuoy
narapady chhuoy
1,775 Points

thank so much I figured out now