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Python Python Basics (2015) Logic in Python Try and Except

Posted by huri ergenian
huri ergenian
1,391 Points

Am I missing something?

Will someone please review my code? There's no clear issue, but it's not accepting my code as right.

trial.py 
def add(num1, num2):

try:
    num1= float(num1)
    num2= float(num2)

except ValueError:
    return(None)

else:
    return(num1+num2)

2 Answers

Andrew Winkler
Andrew Winkler
37,739 Points
Andrew Winkler
Andrew Winkler
37,739 Points

I think you misunderstand the concept of try catch blocks. The function needs to be defined --> then you can try your test. Check this out. 

# define the function
def add (num1, num2):

#now, define the test
  try:
    return float(num1) + float(num2)

# if it fails, define the error message. In this case, there is none.
  except ValueError:
    return None
Carlos Federico Puebla Larregle
Carlos Federico Puebla Larregle
21,074 Points
Carlos Federico Puebla Larregle
Carlos Federico Puebla Larregle
21,074 Points

I think the error is that you are putting parenthesis right after the keywords (return) with no white space between like if you were working with a function instead of a keyword. Try doing it like this:

def add(num1, num2):
    try:      
        num1 = float(num1)
        num2 = float(num2)
    except ValueError:
        return None
    else:
        return num1 + num2

I hope this helps a little bit.