Alright, last step but it's a big one. Make a while loop that runs until start is falsey. Inside the loop, use random.

Question

i need pointers on this please

even.py

import random

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

start = 5
while start:
    random_number = random.randint(1,99)
    if random_number %2 = 0:
        print("{} is even".format(random_number))
    else:
        print("{} is odd".format(random_number))

    start -=1

Answer 1 · 2018-02-05T18:13:52Z

February 5, 2018 6:13pm

You were close but the problem is in your if statement. You are trying to use the assignment operator "=" to test the condition instead of the comparison operator "==".

All you need to do is add anther equals sign and it will pass, like this:

    if random_number % 2 == 0:

Answer 2 · 2018-02-05T18:16:29Z

February 5, 2018 6:16pm

Thank you!

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mamadou diene

mamadou diene

Alright, last step but it's a big one. Make a while loop that runs until start is falsey. Inside the loop, use random.

2 Answers

Connor Walker

Connor Walker

mamadou diene

mamadou diene