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Python Python Basics (2015) Letter Game App Even or Odd Loop

Posted by Bhargav Chava
Bhargav Chava
1,706 Points

Alright, last step but it's a big one. Make a while lo

Alright, last step but it's a big one. Make a while loop that runs until start is falsey. Inside the loop, use random.randint(1, 99) to get a random number between 1 and 99. If that random number is even (use even_odd to find out), print "{} is even", putting the random number in the hole. Otherwise, print "{} is odd", again using the random number. Finally, decrement start by 1. I know it's a lot, but I know you can do it!

even.py 
import random
start=5
while start=False:
        rand=random.randint(1,99)
        even_odd(rand)
        if even_odd(rand)==True:
            print("{} is even".format(rand))
            else:
                print("{} is odd".format(rand)) 
        start-=1 
def even_odd(num)
    return not num % 2
Eddy Hood
Eddy Hood
10,154 Points

What's your specific question?

Bhargav Chava
Bhargav Chava
1,706 Points

i get the error task 1 is not passing

Bhargav Chava
Bhargav Chava
1,706 Points

task 1 is to import random library

2 Answers

Chris Freeman
MOD
Chris Freeman
Treehouse Moderator 68,441 Points
Chris Freeman
Chris Freeman
Treehouse Moderator 68,441 Points

The error "task one is no longer passing" usually means a syntax error was introduced.

The four I see are:

  • A missing colon (:) at the end of the function declaration
  • The function needs to be defined before it is called. Move the code for the even_odd function above the while loop.
  • The else statement is indented too far. It should align with the if statement
  • The while condition cannot be an assignment. However comparing start to False will always be false because start is the number not a Boolean value. You can use one of two options:
    • while start: # use truthiness of start
    • while start > 0:. # check if start positive

Post back if you need more help. Good luck!!!

James Reinhold
James Reinhold
12,361 Points
James Reinhold
James Reinhold
12,361 Points 
import random

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2
#Task 3 of 3 
#Alright, last step but it's a big one.
#Make a while loop that runs until start is falsey. start is truthy)
start = 5
while start:
    # Inside the loop, use random.randint(1, 99) to get a
    # random number between 1 and 99. 
    number = random.randint(1, 99)

    #if that random number is even(use even_odd to find out)...
    if even_odd(number):
        # print "{} is even", putting the random number in the hole.
        print("{} is even".format(number))
        # Otherwise,...
    else:
        # print "{} is odd", again using the random number.
        print("{} is odd".format(number))
        # Finally, decrement start by 1.
    start -= 1