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Jirka Michalik
11,573 PointsAlright, last step but it's a big one.
Hello lads,can anybody help me? It seems that my code is right, but the challenge didn't accept that
import random
start = 5
while start > 0:
rand_number = random.randint(1,99)
start -= 1
if even_odd(rand_number) == True:
print("{} is even".format(rand_number))
else:
print("{} is odd".format(rand_number))
def even_odd(num):
# If % 2 is 0, the number is even.
# Since 0 is falsey, we have to invert it with not.
return not num % 2
3 Answers
Reyam Marcos
Courses Plus Student 10,367 Pointstry this one,
import random
start = 5
def even_odd(num):
# If % 2 is 0, the number is even.
# Since 0 is falsey, we have to invert it with not.
return not num % 2
while start:
number = random.randint(1, 99)
if even_odd(number):
print("{} is even".format(number))
else:
print("{} is odd".format(number))
start -= 1
hope it helps
Thomas Fildes
22,687 PointsHi Jirka,
I used the following code to pass this challenge:
while start:
randomNumber = random.randint(1, 99)
if randomNumber % 2 == 0:
print("{} is even".format(randomNumber))
else:
print("{} is odd".format(randomNumber))
start -= 1
The start variable needs to decrement by 1 after the if statement and the if statement needs to check if the number is even by using modular (%). Hope this helps! Happy Coding!!!
Jirka Michalik
11,573 PointsOkay :) thank you guys