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Python Python Basics (2015) Number Game App Number Game Refinement

Posted by Adam Marasli-Zaade
Adam Marasli-Zaade
2,966 Points

All seem to work fine but whenever I am typing something irrelevant to an int, I get an error.

import random


def game():
  #generate a random number between 1 and 10
  secret_num = random.randint(1, 10)
  guesses=[]

  while len(guesses) < 5:
      try:
          #get a number guess from the player
          guess = int(input("Guess a number betwwen 1 and 10: "))
      except ValueError:
          print("{} isn't a number 'mon.".format(guess))
      else:
          #compare guess to secret number
          if guess == secret_num:
              print("You got it 'mon! My number was {}".format(secret_num))
              break
          elif guess < secret_num:
              print("My number is higher than {} 'mon.".format(guess))
          else:
              print("My number is lowen than {} 'mon.".format(guess))
          guesses.append(guess)
  else:
      print("You didn't get it 'mon. My number was {}.".format(secret_num))
  play_again = input("Do ya want to play again 'mon? Y/n ")
  if play_again.lower() != 'n':
      game()
  else:
       print("Bye 'mon!")


game()

The Error:

Traceback (most recent call last):
File "number_game.py", line 12, in game
guess = int(input("Guess a number betwwen 1 and 10: "))
ValueError: invalid literal for int() with base 10: 'k'

During handling of the above exception, another exception occurred:

Traceback (most recent call last):
File "number_game.py", line 34, in <module>
game()
File "number_game.py", line 14, in game
print("{} isn't a number 'mon.".format(guess))
UnboundLocalError: local variable 'guess' referenced before assignment

what do you think? :) thnx

ps. In memory of Vol'jin. :P

2 Answers

Ryan S
Ryan S
27,276 Points
Ryan S
Ryan S
27,276 Points

Hi Adam,

Your error is the result of trying to convert the input to an int in the same line (line 12).

Say you start the program and enter a non-numeric string as your first guess. It will go to the except: block as you'd expect, but the problem is that in the string format line, you are trying to use the variable "guess" which hasn't actually been defined yet because it threw a ValueError. So then it throws the error that you are receiving.

You can test this another way by guessing a number first, then guessing a non-numeric string on your second try. You'll notice that it won't give you that error, but "guess" will be defined as the last variable that got successfully assigned to it (i.e., the last number you guessed.)

So in order to fix this, you'd need to first assign "guess" to the input prompt (you can do this outside the try block). Then in your try block you'd try to convert it to an int:

while len(guesses) < 5:
    #get a number guess from the player
    guess = input("Guess a number betwwen 1 and 10: ")
    try:
        guess = int(guess)
     except ValueError:
        print("{} isn't a number 'mon.".format(guess))
fahad lashari
fahad lashari
7,693 Points
fahad lashari
fahad lashari
7,693 Points

Thanks so much dude!

Nahum Smith
Nahum Smith
3,699 Points
Nahum Smith
Nahum Smith
3,699 Points

Hi Ryan,

I tried refactoring using your above method and I still seem to be getting the same error: I even eliminated the reference to the guess variable in the exception string, but that ALSO did not work.

Here is my error: Traceback (most recent call last): File "number_game.py", line 50, in <module> guess_a_num_game() File "number_game.py", line 20, in guess_a_num_game guess = input("Guess a number between 1 and 10: ") File "<string>", line 1, in <module> NameError: name 'ba' is not defined

below is the code (obviously):

import random

def play_again(lost):
  if lost == True:
    user_again = input("I'm sorry you you LOST! Try again (yes or no)? ")
  else:
    user_again = input("You got it! My number was {}.  Play again (yes or no)? ".format(secret_num))
  if user_again == 'yes':
    return True
  elif user_again == 'no':
    return False
  else:
    print("That was not a valid response")
    play_again(lost)

def guess_a_num_game():

    secret_num = random.randint(1, 10)
    guess_count = 0
    guess = input("Guess a number between 1 and 10: ")
    try:
        guessInt = int(guess)
    except ValueError:
        print("That isn't a number!")
        guess_a_num_game()
    except NameError:
        print("That isn't a number!")
        guess_a_num_game()
    else:
        while True:
            if guess_count > 2:
                guess_count = 0
                if play_again(True):
                    guess_a_num_game()
                else:
                    break
            elif guessInt == secret_num:
                guess_count = 0
                if play_again(False):
                    guess_a_num_game()
                else:
                    break
            else:
                guess_count += 1
                if guessInt > secret_num:
                    print("Too high! Guess again!")
                else:
                    print("Too low! Guess again!")

guess_a_num_game()
Nilton S Bossolan
PLUS
Nilton S Bossolan
Courses Plus Student 1,047 Points
Nilton S Bossolan
Nilton S Bossolan
Courses Plus Student 1,047 Points

Workaround for this would be to exclude guess input value when printing exception message.

But no idea how to make game print non int in exception.