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Start your free trialFabian Pijpers
Courses Plus Student 41,372 PointsAgain this baffles me. What is wrong with my code?
Where do i go wrong here in this look is it the if statement, the counter being added or the loop itself?
def repeat(string, times)
fail "times must be 1 or more" if times < 1
counter = 0
loop do
# YOUR CODE HERE
repeat("hi", 5)
counter = counter + 1
if counter == times
break
end
end
end
2 Answers
kyle strachan
2,206 PointsYou're over complicating it, the way to do it is replace repeat("hi",5) with print(string), you made it call the method inside the method you're trying to call which is why its failing.
Also instead of counter = counter + 1 put counter += 1 which increments counter with the value after += which must be an int not a string so don't do "1" just do 1
Jeff Muday
Treehouse Moderator 28,720 PointsYou are so close! Nice job. Let's build on that.
The ONLY thing I needed to change to make it work was the repeat
and substitute it with puts
which prints the string (without a newline) each time it goes through the loop.
def repeat(string, times)
fail "times must be 1 or more" if times < 1
counter = 0
loop do
# YOUR CODE HERE
# this line prints the string (once each loop interation)
# this was the ONLY change you needed.
puts(string)
counter = counter + 1
if counter == times
break
end
end
end
Fabian Pijpers
Courses Plus Student 41,372 PointsThanks but this one is already solved