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Start your free trialCourtney Cassar
1,407 PointsAgain, not sure what I'm doing wrong here... even after looking at the solution it's still not working.
it keeps coming up with '(Int) -> String does nor conform to protocol 'Sequence' could someone explain what this error means? I am taking an Int and it is outputting a string
func fizzBuzz(n: Int) -> String {
// Enter your code between the two comment markers
for n in fizzBuzz {
if (n % 3==0) && (n % 5)==0 {
print("FizzBuzz")
} else if (n % 3==0) {
return"Fizz"
} else if (n % 5 == 0){
return"Buzz"
} else {
return(n)}
}
}
// End code
1 Answer
Aniruddha Shukla
2,846 PointsYour syntax is wrong. The default case you are returning an Integer when your function is saying it returns a String. This should work
func fizzBuzz(n: Int) -> String {
// Enter your code between the two comment markers
if ((n % 3 == 0) && (n % 5 == 0)) {
return "FizzBuzz"
} else if (n % 3==0) {
return"Fizz"
} else if (n % 5 == 0){
return"Buzz"
}
return "\(n)"
}