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Java Java Basics Perfecting the Prototype String Equality

Posted by Adwaina Richardson
Adwaina Richardson
3,733 Points

Add another if statement that checks if the firstExample is equal ignoring case to thirdExample. If it, is print out

My answer but keeps saying it's wrong. Please tell me what I'm doing wrong.

if (firstExample.equalsIgnoreCase("HELLO")) { console.printf("first is equal to second");

Equality.java 
// I have imported a java.io.Console for you, it is named console. 


String firstExample = "hello";
String secondExample = "hello";
String thirdExample = "HELLO";

 // if  (firstExample.equals("hello"))  {
 // console.printf("first is equal to second");

  if (firstExample.equalsIgnoreCase("HELLO"))  {
   console.printf("first and third are the same ignoring case");

}
Jamie W.
Jamie W.
Courses Plus Student 3,931 Points
Jamie W.
Jamie W.
Courses Plus Student 3,931 Points

It's supposed to be

if (firstExample.equalsIgnoreCase(thirdExample)) {