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17,062 Pointsa question about reduce with spread operator
lets say we have this multi-demsional arr:
const movies = [
['The Day the Earth Stood Still', 'Superman', 'Ghostbusters'],
['Finding Dory'],
['Jaws', 'On the Waterfront']
]
and the solution :
conactWithSpread = movies.reduce((myArr,bookTitle) => [...myArr,...bookTitle],[]);
console.log("Here with spread:",conactWithSpread);
which will print :
[
'The Iliad',
'The Brothers Karamazov',
'Tenth of December',
'Cloud Atlas',
'One Hundred Years of Solitude',
'Candide'
]
why would i need to add ...myArr if the ...bookTile is refercing the elements in the arr?
1 Answer
Steven Parker
231,184 PointsThe "reduce" function builds the result item by item, and the first argument ("myArr" in this case) is the accumulator for the result.
So for each item, "...myArr
" represents all the titles seen so far, and "...bookTitle
" represents the titles in the current item. By replacing "myArr" with "[...myArr, ...bookTitle]
", the new titles are effectively added onto the existing collection. That way, when the function is complete, the resulting array will contain all the titles from all the sub-arrays of the original.
You can also omit the final argument here, since the first item will be a suitable starting value for the accumulator.
But there's something odd about this example, as the output shown contains entirely different titles than the ones present in the original array