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Alex _
17,107 PointsYou could break the number like this:
binary: 00000111
--------
1 X 1 = 1
2 X 1 = 2
4 X 1 = 4
8 X 0 = 0
16 X 0 = 0
32 X 0 = 0
64 X 0 = 0
128 X 0 = 0
--------
Total of all the digits' values:
decimal: 7
starting from the right in binary, each digit's value when it is on or a 1 (same thing) is doubled as you go through the numbers. It's value is always 0 if it is off or 0
For example, if we changed the original number from 00000111 to 10000111 (changed the 8th digit from the right from 0 to 1) we would be adding 128 to the number, since that digit is worth 128 when "on"(1) and 0 when "off"(0)
binary: 10000111
--------
1 X 1 = 1
2 X 1 = 2
4 X 1 = 4
8 X 0 = 0
16 X 0 = 0
32 X 0 = 0
64 X 0 = 0
128 X 1 = 128
--------
Total of all the digits' values:
decimal: 135
Hope this helps.
Thanks Simon for pointing out error
Simon Coates
28,694 PointsSimon Coates
28,694 Pointsyou forgot to change the 1 in 128 X 0 on the second demo.
Abdulrahman Mousa
2,276 PointsAbdulrahman Mousa
2,276 PointsVery helpful, thank you!!