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4,387 PointsWe're in a movie database. There's a reviews table with the columns of id, movie_id, username, rev
I AM NOT SURE WHAT I AM DOING WRONG HERE:
SELECT AVG("rating") AS "average_rating" WHERE movie_id = 6;
1 Answer
Jassim Alhatem
20,883 PointsRemove the quotation, change it to AVG(rating)
Unsubscribed User
4,387 PointsUnsubscribed User
4,387 PointsNo still says "There's something wrong with your SQL statement. Please review your code and try again."
Jassim Alhatem
20,883 PointsJassim Alhatem
20,883 PointsNirujan Baheerathan, my apologies for the late response. You also forgot the
FROM reviews
. So it's going to beSELECT AVG(rating) AS "average_rating" FROM reviews WHERE movie_id = 6;